So the human body surface can accommodate 20 × 30 = 60 dildos

Case A:  If all 60 dildos are identical

For 1 dildo , no. of configurations = 60

For 2 dildos, no. of configurations = 60x59/1×2

For r dildos, no. of configuration2 = 60x59×....×(60 - r + 1)/1×2×...× r

....

The sum of above to 60 dildos=sum of coefficients of (1+x)^60 - 1= 2^60 - 1= 1,152,921,504,606,846,975>10^18

Case B:  If all 60 dildos are different(size, shape.. color)

For 1 dildo , no. of configurations = 60x[60]   -----(2nd factor is number of choice of dildos)

For 2 dildos, no. of configurations = 60x59 x [60x59/1x2]

For r dildos, no. of configurations = 60x59×....×(60 - r + 1) x [60x59×....×(60 - r + 1)/ r! ]

For 60 dildos, no. of configurations = 60x59×....×3×2×1 x [60x59×....×3×2×1/60!]= 60! ≈ 8.32 × 10^81

The last term is as numerous as the number of atoms in the universe:10^78 to 10^82

https://www.thoughtco.com/number-of-atoms-in-the-universe-603795#:~:text=Overall%2C%20the%20estimates%20of%20the,based%20on%20what%20we%20know.